4c^2+9c+5=

Solution for 4c^2+9c+5= equation:

Simplifying
4c2 + 9c + 5 = 0

Reorder the terms:
5 + 9c + 4c2 = 0

Solving
5 + 9c + 4c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(5 + 4c)(1 + c) = 0

Subproblem 1
Set the factor '(5 + 4c)' equal to zero and attempt to solve:

Simplifying
5 + 4c = 0

Solving
5 + 4c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + 4c = 0 + -5

Combine like terms: 5 + -5 = 0
0 + 4c = 0 + -5
4c = 0 + -5

Combine like terms: 0 + -5 = -5
4c = -5

Divide each side by '4'.
c = -1.25

Simplifying
c = -1.25
Subproblem 2
Set the factor '(1 + c)' equal to zero and attempt to solve:

Simplifying
1 + c = 0

Solving
1 + c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + c = 0 + -1
c = 0 + -1

Combine like terms: 0 + -1 = -1
c = -1

Simplifying
c = -1
Solution
c = {-1.25, -1}